wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

cosAsinA+1cosA+sinA1=cosecA+cotA using the identity cosec2A=1+cot2A

Open in App
Solution

cosAsinA1cosA+sinA1=cscA+cotA
LHS
Dividing number and denominator by cossinA
cotA1+cscAcotA+1cscA[ csc2A=1+cotA]
(cscA+cotA)(csc2Acot2A)cotA+1cscA
(cscA+cotA)[(cscA+cotA)(cscAcotA)]cotA+1cscA
(cscA+cotA)(1=cscA+cotA)cotA+1cscA
cscA+cotA
RHS
Here proved


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle and Its Measurement
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon