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Byju's Answer
Standard XII
Mathematics
Circular Measurement of Angle
cos A -sin A+...
Question
cos
A
−
sin
A
+
1
cos
A
+
sin
A
−
1
=
c
o
s
e
c
A
+
cot
A
using the identity
c
o
s
e
c
2
A
=
1
+
cot
2
A
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Solution
cos
A
−
sin
A
−
1
cos
A
+
sin
A
−
1
=
csc
A
+
cot
A
L
H
S
⇒
Dividing number and denominator by
cos
sin
A
cot
A
−
1
+
csc
A
cot
A
+
1
−
csc
A
[
∵
csc
2
A
=
1
+
cot
′
A
′
]
⇒
(
csc
A
+
cot
A
)
−
(
csc
2
A
−
cot
2
A
)
cot
A
+
1
−
csc
A
⇒
(
csc
A
+
cot
A
)
−
[
(
csc
A
+
−
cot
A
)
(
csc
A
−
cot
A
)
]
cot
A
+
1
−
csc
A
⇒
(
csc
A
+
cot
A
)
−
(
1
=
csc
A
+
cot
A
)
cot
A
+
1
−
csc
A
⇒
csc
A
+
cot
A
⇒
R
H
S
Here proved
Suggest Corrections
4
Similar questions
Q.
cos
A
−
sin
A
+
1
cos
A
+
sin
A
−
1
=
cos
e
c
A
+
cot
A
,
using the identity
cos
e
c
2
A
=
1
+
cot
2
A
.
Q.
Prove that
cos
A
+
sin
A
−
1
cos
A
−
sin
A
+
1
=
1
cosec
A
+
cot
A
, using the identity
cosec
2
A
−
cot
2
A
=
1.
Q.
State whether the following statement is true or false.
cos
A
−
sin
A
+
1
cos
A
+
sin
A
−
1
=
cosec
A
+
cot
A
. (by using the identity
cosec
2
A
=
1
+
cot
2
A
.
)
Q.
c
o
s
A
−
s
i
n
A
+
1
c
o
s
A
+
s
i
n
−
1
=
c
o
s
e
c
A
+
c
o
t
A
,
, using the identity
c
o
s
e
c
2
A
=
1
+
c
o
t
2
A
.
Q.
cos
A
−
sin
A
+
1
cos
A
+
sin
A
−
1
=
csc
A
+
cot
A
, using the identity
csc
2
A
=
1
+
cot
2
A
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