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Question

cosAsinA+1cosA+sinA1=cosecA+cotA using the identity cosec2A=1+cot2A

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Solution

cosAsinA1cosA+sinA1=cscA+cotA
LHS
Dividing number and denominator by cossinA
cotA1+cscAcotA+1cscA[ csc2A=1+cotA]
(cscA+cotA)(csc2Acot2A)cotA+1cscA
(cscA+cotA)[(cscA+cotA)(cscAcotA)]cotA+1cscA
(cscA+cotA)(1=cscA+cotA)cotA+1cscA
cscA+cotA
RHS
Here proved


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