$\frac{cos 51^{o}}{sin 39^{o}} + cos 52^{o} cosec 38^{o}$

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\frac{1}{2}

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Solution

The correct option is C $2$
$\frac{cos 51^{o}}{sin 39^{o}} + cos 52^{o} cosec 38^{o}$

$= \frac{cos 51^{o}}{sin 39^{o}} + \frac{cos 52^{o}}{sin 38^{o}}$

$= \frac{cos (90^{o} - 39^{o})}{sin 39^{o}} + \frac{cos (90^{o} - 38^{o})}{sin 38^{o}}$

$= \frac{sin 39^{o}}{sin 39^{o}} + \frac{sin 38^{o}}{sin 38^{o}}$

$= 1 + 1 = 2$

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