CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

sinA+sinB+sinCsinA+sinBsinC=cotA2cotB2.

Open in App
Solution

sinA+sinB+sinCsinA+sinBsinC
=2sin(A+B2)cos(AB2)+2sin(A+B2cos(A+B2)2sin(A+B2)cos(AB2)2sin(A+B2cos(A+B2)
=cos(AB2)+cos(A+B2)cos(AB2)cos(A+B2)
=2cosA2cosB22sinA2sinB2
=cotA2cotB2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Derivative of Standard Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon