CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

x2yxy2=xy Find dydx

Open in App
Solution

x2yxy2=xyddxxy(x)xy(y)=ddxxy1y=y+xdydxdydx=1y2xy

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Implicit Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon