Question

Diagonals of a rhombus are $12cm$ and $16cm$ respectively, then find the side of rhombus and its perimeter.

Answer 1

REF.Image.

As diagonals of

rhombus are perpendicular

bisectors of each other,

$\Rightarrow OA=6,OB=8,$ In $△AOB$ by Pythagoras

theorem, $A{B}^2=6^2+8^2\Rightarrow AB=\sqrt{100}=10cm$

As all sides of rhombus are equal,

$\Rightarrow AB=BC=CD=DA=10cm$

Perimeter = $4\times 10=40cm$