Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of Section BEFC of the frame, if the width of each section is same.
96 Square cm.
Given that, the width of each Section is same.
Therefore, IB = BJ= CK =CL = DM = DN = AO =AP
IL= IB +BC + CL
28= IB + 20 +CL
IB+CL =28cm - 20 cm = 8cm
IB =CL = 4cm
Hence, IB =BJ=CK=CL=DM=DN=AO=AP=4cm
Area of Section BEFC =Area of section DGHA
=12(20+28)(4)]cm2=96cm2