Question

Diameter of a circle is $26$ cm and length of a chord of the circle is $24$ cm. find the distance of the chord from the centre.

Answer 1

R.E.F image

Given diameter of circle = 26 cm

diameter =2r = 26 cm

radius = 13 cm

length of chord of circle = 24 cm

Given OA = 13 cm

$AC=\frac{AB}{2}=12cm$

$\therefore OC=\sqrt{O{A}^2-A{C}^2}$ (By Pythagoras theorem)

$=\sqrt{(13{)}^2-(12{)}^2}$

$=\sqrt{169-144}$

$=\sqrt{25}=5cm$