Question

Length of a chord of a circle is $24$ cm and its distance from the centre is $5$ cm. Find the diameter of the circle.

Answer 1

$H^2=B^2+P^2$

Then given that

Distance between chord from radius $=5$ cm

Length of chord $=24$ cm

$H^2=B^2+P^2$

$H=\sqrt{(12{)}^2+(5{)}^2}$

$\Rightarrow H=\sqrt{144+25}$

$\Rightarrow H=\sqrt{169}$

$\Rightarrow H=\sqrt{(13{)}^2}$

$\Rightarrow H=13$cm

$\therefore$ Radius of the circle $=13$ cm.

Diameter of the circle $=2\times radius=2\times 13=26$cm.