Question

# Diameter of a circle is $$26$$ cm and length of a chord of the circle is $$24$$ cm. find the distance of the chord from the centre.

Solution

## R.E.F image Given diameter of circle = 26 cm diameter =2r = 26 cm radius = 13 cm length of chord of circle = 24 cm Given OA = 13 cm $$AC = \frac{AB}{2} = 12 cm$$$$\therefore OC = \sqrt{OA^{2}-AC^{2}}$$ (By Pythagoras theorem)$$= \sqrt{(13)^{2}-(12)^{2}}$$$$= \sqrt{169-144}$$$$= \sqrt{25} = 5 cm$$Mathematics

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