Question

Diborane $\left(B_2{H}_6\right)$ reacts independently with $O_2$ and $H_{2}O$ to produce, respectively.

• A. $B_2{O}_3$ and $H_{3}B{O}_3$
• B. $B_2{O}_3$ and $[B{H}_4{]}^{-}$
• C. $H_{3}B{O}_3$ and $B_2{O}_3$
• D. $HB{O}_2$ and $H_{3}B{O}_3$

Answer 1

The correct option is A $B_2{O}_3$ and $H_{3}B{O}_3$

Diborane $\left(B_2{H}_6\right)$ reacts independently with $O_2$ and $H_{2}O$ to produce $B_2{O}_3$ and $H_{3}B{O}_3$ respectively.

Diborane is a colourless, highly toxic gas, having boiling point 180 K. Because of its inflammable nature it catches fire spontaneously when exposed to air and burns in oxygen releasing an enormous amount of energy as:
$B_2{H}_6+3O_2\to B_2{O}_3+3H_{2}O\Delta H=+1976kJ/mol$
It gets hydrolysed readily to give boric acid.
$\underset{\text{Borane}}{B_2{H}_6}+6H_{2}O\to \underset{\text{Orthoboric acid}}{2H_{3}B{O}_3}+\underset{\text{Dihydrogen}}{6H_2\uparrow }$
Hence correct option is a.