Differentiate and find dydx - tan x-y- x-3x2

tanx+y=secx 3x^2 sec^2x+dydx=secxtanx 6x dydx=secxtanx 6x sec^2x ...

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Implicit Differentiation

Differentiate...

Question

Differentiate and find $\frac{d y}{d x}$ :
$tan x + y = sec x - 3 x^{2}$

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Solution

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\frac{d y}{d x}

3 x^{2} + t a n x + s e c x = y + 6

(x)^{t a n x} + (t a n x)^{x} t h e n f i n d \frac{d y}{d x}

y = tan x + cot x

\frac{d y}{d x}

For the given differential equation find the general solution.

$c o s^{2} d x \frac{d y}{d x} + y = t a n x (0 \leq x < \frac{p i}{2})$

c o s^{2} x \frac{d y}{d x} + y = t a n x

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