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Question

Differentiate x2sinx1x w.r.t x

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Solution

y=x2sinx1x using quotient rule of differentiateion.
dydx=(1x)ddx(x2sinx)x2sinxddx(1x)(1x)2
=(1x)[2xsinx+x2cosx]x2sinx(1)(1x)2
=(2xsinx+x2cosx2x2sinxx3cosx+x2sinx)(1x)2
=x3cosx+x2(cosxsinx)+2xsinx(1x2)


1257543_1331569_ans_27780fd7692f409bb8d9901183c181bb.PNG

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