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Question

Differentiate given problems w.r.t.x.

(5x)3 cos 2x

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Solution

Let y = (5x)3 cos 2x

Taking log on both sides, we get log y = log (5x)3 cos 2x=3 cos 2x (log 5x) Differentiating w.r.t x. we get

1ydydx=3cos2xddx(log5x)ddx(3cos2x)

=(3cos2x)(55x,5)+(log5x)[3(sin2x).2]

(Using product ruleddx(u.v)=uddxv+vddxu)

dydx=y{3 cos 2xx6(sin 2x)(log 5x)}

dydx=(5x)3 cos 2x{3 cos 2xx6 sin 2x log 5x}


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