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Question

Differentiate the following function:
(sinx)x+sin1x

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Solution

y=(sinx)x+sin1(x)

u=(sinx)x
logu=xlog(sinx)

1u=dudx=xcosxsinx+log(sinx)
dudx=(xcotx+log(sinx))(sinx)x..........(1)
v=sin1x

dvdx=11x(12x)

dvdx=12x(1x)........(2)

dydx=dudx+dvdx

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