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Byju's Answer
Standard IX
Mathematics
Values of Trigonometric Ratios
Differentiate...
Question
Differentiate the following function:
(
sin
x
)
x
+
sin
−
1
√
x
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Solution
y
=
(
sin
x
)
x
+
sin
−
1
(
√
x
)
u
=
(
sin
x
)
x
⇒
log
u
=
x
log
(
sin
x
)
⇒
1
u
=
d
u
d
x
=
x
cos
x
sin
x
+
log
(
sin
x
)
⇒
d
u
d
x
=
(
x
cot
x
+
log
(
sin
x
)
)
(
sin
x
)
x
..........(1)
v
=
sin
−
1
√
x
⇒
d
v
d
x
=
1
√
1
−
x
(
1
2
√
x
)
⇒
d
v
d
x
=
1
2
√
x
(
1
−
x
)
........(2)
∴
d
y
d
x
=
d
u
d
x
+
d
v
d
x
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