Differentiate the following functions with respect to x :

2 sec x + 3 cot x - 4 tan x

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Solution

We have,

$\frac{d}{d x} (2 s e c x + 3 c o t x - 4 t a n x)$

$= 2 \frac{d}{d x} (2 s e c x) + 3 \frac{d}{d x} (c o t x) - 4 \frac{d}{d x} (t a n x)$

$= 2 s e c x t a n x - 3 c o s e c^{2} x - 4 s e c^{2} x$

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