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Question

Differentiate the following w.r.t.x:
sin(2cos1x)

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Solution

Let y=sin(2cos1x)

On differentiating w.r.t x, we get
dydx=ddx[sin(2cos1x)]

dydx=cos(2cos1x)ddx(2cos1x)

dydx=[cos(2cos1x)]×2×11x2

dydx=2[cos(2cos1x)]1x2

Hence, this is the answer.

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