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Question

Differentiate the function (sinx)x+sin1x with respect to x.

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Solution

D=ddx(((sinx)x(A))+((sin1x)(B)))
Addx(exln(sinx))
exln(sinx)(ln(sinx)+xcotx)
(sinx)x(ln(sinx)+xcotx)
Bddx(sin1x)
=11(x)2.12x
=11x.12x
D=sinx(x)(ln(sinx)+xcotx)+12x11x

1116220_1139969_ans_ecac78d6e7f74bc6b2b0032b61c50159.jpeg

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