Diffraction of sound is very easy, to observe in day-to-day life. This is not so with light. This is so because
A
λS>λL
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B
λS<λL
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C
light waves are transverse and sound waves are longitudinal
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D
λS=λL
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Solution
The correct option is AλS>λL A wavelength of light λL is comparable to the size of the obstacles while the wavelength of sound λS is much greater than that of light and henceforth to that of the obstacle.