Dimensional formula for capacitance is:

M^{- 1} L^{- 2} T^{4} I^{2}

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M^{1} L^{2} T^{4} I^{- 2}

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M^{1} L^{2} T^{2}

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{M L T}^{- 1}

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Solution

The correct option is A $M^{- 1} L^{- 2} T^{4} I^{2}$
$E = \frac{Q^{2}}{2 C}$
Dimensions of C will be dimension of $\frac{Q^{2}}{E}$ $= \frac{I^{2} T^{2}}{M L^{2} T^{- 2}}$ $= M^{- 1} L^{- 2} T^{4} I^{2}$
Hence, option A is correct.

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Similar questions

[M^{1} L^{2} T^{- 3} A^{- 2}]

M^{1} L^{2} T^{3} I^{- 1}

[M^{1} L^{2} T^{- 2}]

\frac{P}{Q}

[M^{1} L^{0} T^{- 2}]

M^{- 1} L^{- 2} T^{4} A^{2}

ϵ_{0}

μ_{o}

=

=

=

=

ϵ_{0} = M^{- 1} L^{- 3} T^{2} I

ϵ_{0} = M^{- 1} L^{- 3} T^{4} I^{2}

μ_{0} = {M L T}^{- 2} I^{- 2}

ϵ_{0} = {M L}^{2} T^{- 1} I

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