Question

Let ${ϵ}_0$ denote the permittivity of the vacuum and ${\mu }_o$ is permeability of vacuum.
If M$=$mass, L$=$length, T$=$time and I $=$ electric current, then
a) ${ϵ}_0=M^{-1}{L}^{-3}{T}^{2}I$
b) ${ϵ}_0=M^{-1}{L}^{-3}{T}^4{I}^2$
c) ${\mu }_0={MLT}^{-2}{I}^{-2}$
d) ${ϵ}_0={ML}^2{T}^{-1}I$

• A. a & c are correct
• B. b & c are correct
• C. c & d are correct
• D. d & a are correct

Answer 1

Answer: (B)

b & c are correct

Vaccum permittivity:

$F_c=\frac{1}{4\pi {\epsilon }_0}\times \frac{q_1{q}_2}{r^2}$

Where ${\epsilon }_0$ is permttivity of vaccum.

Dimension will be $\left[M^{-1}{L}^{-3}{T}^4{I}^2\right]$

Vaccum permeability:

${\mu }_0=4\pi \times {10}^{-7}N/A^2$

Dimensions will be $\left[ML{T}^{-2}{I}^{-2}\right]$

B and C are correct.