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Question

Let [ε0] denote the dimensional formula of the permittivity of the vaccum and [μ0] denote the permeability of the vacuum. If M= mass, L= length, T= time and I= electric current, then
  1. (ε0]= M1L3T2I
  2. (ε0]=M1L3T4I2
  3. (μ0]=MLT2I2
  4. (μ0]=ML2T1I


Solution

The correct options are
B (ε0]=M1L3T4I2
C (μ0]=MLT2I2
 Unit of ε0=C2Nm2(ε0]=I2T4ML3=(M1L3T4I2]
We know that μ0ϵ0= 1c2 (where c is the velocity of light)
Using this we can say [μ0]= [MLT2I2] 

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