Question

Dipole moment of $HCl$ molecule is found to be $0.816D$. Assuming $HCl$ bond length to be equal to $1\mathring{A}$, the % ionic character of $HCl$ molecule is:

• A. $10\%$
• B. $17\%$
• C. $27\%$
• D. $37\%$

Answer 1

The correct option is B $17\%$

The $\%$ ionic character of $HCl$ molecule is $17\%$.

${\mu }_m=\delta \times d$

$0.816\times {10}^{-18}=\delta \times {10}^{-18}$

$\delta =0.816\times {10}^{-10}esu$
$\therefore$ Ionic character$=\frac{0.816\times {10}^{-10}}{4.803\times {10}^{-10}}\times 100=16.9\%$.