wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Direction(1-4): Read the following information carefully and answer the following questions that follow:

Mr. Sharma, a truck driver drives his truck every day. He travels a different distance by his truck on each day.

The pie chart given below shows the percentage of distance travelled on a particular day (one out of Monday to Friday) out of the total distance that he travelled in the five days (Monday-Friday) of a particular week.

Days Speed ( in km/ hr0 Monday Tuesday Wednesday Thursday Friday
------
52
------
68
------

Total distance travelled by the truck = 2000 Km

The table given below shows the average speed (in km/hr) of Mr. Sharma's truck on the five weekdays. Some of the data is missing.

If the average speed of the truck on Wednesday is 34ths
ths of the average speed of the truck on Thursday, find the ratio of time for which the truck travels on Tuesday and Wednesday.


A
2 : 1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1 : 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5 : 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10 : 7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2 : 1

Distance travelled on Monday = 22% of 2000 = 440 km

Similarly,

Day Distance Travelled (in km) Monday Tuesday Wednesday Thursday Friday
440
520
255
340
445


Time for which Mr. Sharma travelled on Tuesday = 52052=10hrs

Time for which Mr. Sharma travelled on Thursday = 34068=5hrs

Average speed of the truck on Wednesday = 68×34=51km/hr

Time for which the truck travels on Wednesday = 25551=5hrs

Required ratio = 10 : 5 = 2 : 1


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inferring from Double Bar Graphs
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon