The correct option is D ( 5a+2b ) ( 5a 2b+1 ) 25a^2 4b^2+5a+2b = #160; ( 5a )^2 ( 2b )^2+ ( 5a+2b ) = #160; ( 5a+2b ) ( 5a 2b )+ ...

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Factorisation Using Algebraic Identities

25a2-4b2+5a+2...

Question

$25 a^{2} - 4 b^{2} + 5 a + 2 b$ =_______

(5 a + 2 b - 1) (5 a - 2 b)

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(5 a + 2 b + 1) (5 a - 2 b)

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(5 a + 2 b) (5 a - 2 b - 1)

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(5 a + 2 b) (5 a - 2 b + 1)

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Solution

The correct option is D $(5 a + 2 b) (5 a - 2 b + 1)$
$25 a^{2} - 4 b^{2} + 5 a + 2 b$
= ${(5 a)}^{2} - {(2 b)}^{2} + (5 a + 2 b)$
= $(5 a + 2 b) (5 a - 2 b) + (5 a + 2 b)$
= $(5 a + 2 b) (5 a - 2 b + 1)$

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Similar questions

If $\frac{5 a + 2 b}{5 a - 2 b} = \frac{5}{3}$ , then a : b =

$25 a^{2} - 4$ can be factorized as:

3 a^{2} b

- 5 a^{2} b

\frac{5 a + 2 b}{5 a - 2 b} = \frac{5}{3}

3 a (a - 2 b + 3 c)

4 a (5 a + 2 b - 3 c)

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