$2 x^{2} + 11 x + 14$ =________

(2 x + 2) (x + 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 x + 7) (x + 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 x + 7) (x + 2)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2 x + 4) (x + 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(2 x + 7) (x + 2)$
$2 x^{2} + 11 x + 14$
$= 2 x^{2} + 7 x + 4 x + 14$
$= 2 x (x + 2) + 7 (x + 2)$
$= (2 x + 7) (x + 2)$

Suggest Corrections

Similar questions

Factorize $2 x^{2} - 7 x + 5 = 0$

∣ ∣ ∣ ∣ \begin{matrix} x + 1 & x + 2 & x + 4 x + 3 & x + 5 & x + 8 x + 7 & x + 10 & x + 14 \end{matrix} ∣ ∣ ∣ ∣ =

\int \frac{4 x - 7}{2 x^{2} - 7 x + 6} d x

2 x^{7} - 128 x

\frac{x^{2} - 7 x + 10}{x^{2} - 5 x - 14} \times \frac{x^{3} + 8}{x^{3} - 8} \times \frac{x^{2} + 2 x + 4}{x^{2} - 2 x + 4} \times \frac{x - 7}{x - 5} = ?

Join BYJU'S Learning Program