Question

$62.5\times {10}^6$ electrons per second are flowing through a wire of cross section area . The value of current flowing will be:

• A. $1\times {10}^{2}A$
• B. 10A
• C. $1\times {10}^{-11}A$
• D. 6A

Answer 1

The correct option is C $1\times {10}^{-11}A$

Given : $n=62.5\times {10}^6$ electrons $t=1$ s $q=1.6\times {10}^{-19}$ C

$\therefore$ Electric current $I=\frac{nq}{t}=\frac{62.5\times {10}^6\times 1.6\times {10}^{-19}}{1}=1\times {10}^{-11}$ A