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Question

(6ab3abc+9abcd)÷(13ab) is equal to

A
2+c+3cd
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B
2+c3cd
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C
18+9c27cd
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D
189c27cd
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Solution

The correct option is C 18+9c27cd
6ab3abc+9abcd13ab
By separating denominators, we get

=6ab13ab+(3abc)13ab+9abcd13ab
=6abab×(3)+(3abc)ab×(3)+(9abcd)ab×(3)
=18+9c27cd
Hence final value after given operation is 18+9c27cd

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