Question

$A_{organicCompound}+O_2\to X+Y+Z$
Compound ( A ) in pure form does not give ppt. with $AgN{O}_3$ solution. A mixture containing 70% of ( A ) and 30% of ether is used as an anaesthetic. Compound ( X ) and ( Y ) are oxides while ( Z ) is a pungent smelling gas. ( X ) is a neutral oxide which turns cobalt chloride paper pink. Compound ( Y ) turns lime water milky and produces an acidic solution with water. Compounds ( A ), ( X ), ( Y ) and ( Z ) respectively will be :

• A. $C{H}_4,H_{2}O,C{O}_2,C{l}_2$
• B. $CHC{l}_3,H_{2}O,C{O}_2,C{l}_2$
• C. $C{H}_{3}OH,H_{2}O,C{O}_2,N_2$
• D. $N{H}_{2}CON{H}_2,H_{2}O,N_{2}O,C{O}_2$

Answer 1

Answer: (B)

$CHC{l}_3,H_{2}O,C{O}_2,C{l}_2$

$CHC{l}_3+O_2\to H_{2}O+C{O}_2+C{l}_2$
A is $CHC{l}_3$, X is $H_{2}O$, Y is $C{O}_2$ and Z is $C{l}_2$.
Chloroform($CHC{l}_3$) is a pure covalent compound and the chlorine atoms are covalently bonded with the Carbon atoms so, they can not ionize in the $AgN{O}_3$ solution to form the precipitate of silver chloride. A mixture containing 70% of $CHC{l}_3$ and 30% of ether is used as an anaesthetic.
Both anhydrous copper sulfate paper and anhydrous (blue) cobalt chloride paper can test for liquid or vaporous water. The copper sulfate paper goes from white to blue. And the cobalt chloride paper goes from blue to pink. In both cases the color change is due to the compounds in the paper combining with water molecules to make a hydrate. $C{O}_2$ turns lime water milky and produces an acidic solution with water.
$CaO+C{O}_2\to CaC{O}_3$
$CaC{O}_3$ is milky in appearance.
$H_{2}O+C{O}_2\to H_{2}C{O}_3$
$H_{2}C{O}_3$ is a weak acid.
$Cl$ is pungent smelling gas.