Question

$C_2{H}_{5}OH$ can be differentiated from ${CH}_{3}OH$ by:

• A. reaction with $HCl$
• B. reaction with ${NH}_3$
• C. by iodoform test
• D. by solubility in water

Answer 1

The correct option is C by iodoform test

$C_2{H}_{5}OH$ can be differentiated from ${CH}_{3}OH$ by iodoform test.

Ethanol can be oxidized to acetaldehyde which contains $C{H}_{3}CO$ group. Hence, it gives a positive iodoform test in which yellow ppt of iodoform is obtained.

Methanol can be oxidized to formaldehyde which does not contain $C{H}_{3}CO$ group. Hence, it does not give a positive iodoform test.

Hence, the correct option is $\text{C}$