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Question

CH3CH2Br(i)Li−−−−−−(ii)CuBr,Δ(A)CH3Cl−−−−Δ(B)

A
(A)[CH3CH2]2CuLi(B)CH3CH2CH3
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B
(A)CH3CH2Br (B) CH3CH2CH3
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C
(A)[CH3CH2]2CuLi(B)CH3CH2CH2Cl
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D
(A)CH3CH2Br (B) CH3CH2CH2Cl
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Solution

The correct option is A (A)[CH3CH2]2CuLi(B)CH3CH2CH3
Ethyl bromide reacts with Li followed by the action of cuprous bromide to form diethyl lithium cuprate (compound A).

Compound (A) on heating with methyl chloride forms n propane (compound B).

CH3CH2Br(i)Li−−−−−−(ii)CuBr,Δ[CH3CH2]2CuLi(A)CH3Cl−−−−ΔCH3CH2CH3(B)

Thus, (A)[CH3CH2]2CuLi(B)CH3CH2CH3

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