${C o C l}_{2}$ gives blue colour with ${N H}_{4} S C N$ in an ethereal layer due to the formation of :

({N H}_{4})_{2} [{C o (S C N)}_{4}]

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({N H}_{4})_{4} [{C o (S C N)}_{6}]

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({N H}_{4})_{3} [{C o (S C N)}_{6}]

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({N H}_{4})_{3} [{C o (S C N)}_{4}]

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Solution

The correct option is A $({N H}_{4})_{2} [{C o (S C N)}_{4}]$
${C o C l}_{2}$ gives blue colour with ${N H}_{4} S C N$ in an ethereal layer due to the formation of $({N H}_{4})_{2} [{C o (S C N)}_{4}]$ .
${C o C l}_{2} + 4 {N H}_{4} S C N \to ({N H}_{4})_{2} [{C o (S C N)}_{4}] + 2 N H_{4} C l$

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