${C r (O H)}_{3}$ is made soluble in $N a O H$ in presence of $H_{2} O_{2}$ when ${N a}_{2} {C r O}_{4}$ of yellow colour is formed and gives yellow ppt. of ${P b C r O}_{4}$ when $({C H}_{3} C O O)_{2} P b$ is added.

If the given statement is true enter 1 else enter 0.

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Solution

${C r (O H)}_{3}$ is made soluble in $N a O H$ in presence of $H_{2} O_{2}$ . when ${N a}_{2} {C r O}_{4}$ of.yellow colour is formed and gives yellow ppt. of ${P b C r O}_{4}$ when. $({C H}_{3} C O O)_{2} P b$ . is added.

$2 C r (O H)_{3} + 4 N a O H + 3 H_{2} O_{2} ⇌ 2 N a_{2} C r O_{4} + 8 H_{2} O$

$N a_{2} C r O_{4} + (C H_{3} C O O)_{2} P b \to P b C r O_{4} ↓ y e l l o w p r c p i t a t e$

Thus, the given statement is true.

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