Question

$\Delta ABC$ and $\Delta PQR$ are similar triangles such that $\angle A={32}^o$ and $\angle R={65}^o$, then $\angle B$ is:

• A. ${83}^o$
• B. ${32}^o$
• C. ${65}^o$
• D. ${97}^o$

Answer 1

Answer: (A)

${83}^o$

Given triangles ABC and PQR are similar.

Hence, $\angle A=\angle P,\angle B=\angle Qand\angle C=\angle R$.

Also known $\angle A=\angle P={32}^o,\angle B=\angle Qand\angle C=\angle R={65}^o$.

Hence, by angle sum property of a triangle, $\angle B={180}^o-({32}^o+{65}^o)={83}^o$.