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Properties of 30°-60°-90° Triangles

CPPA= m3.Find...

Question

$\frac{C P}{P A} = \frac{m}{3}$ .Find $m$

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Solution

In $△ C A B$ and $△ C P Q$ ,
$∠ A C B = ∠ P C Q$ (Common angle)
$∠ C A B = ∠ C P Q$ (Corresponding angles)
$∠ C B A = ∠ C Q P$ (Corresponding angles)
Thus, $△ C A B \sim △ C P Q$ (AAA rule)
$\frac{C P}{C A} = \frac{C Q}{C B}$
$\frac{C P}{C A} = \frac{4.8}{4.8 + 3.6}$
$\frac{C P}{C P + A P} = \frac{4.8}{8.4}$
$84 C P = 48 C P + 48 A P$
$36 C P = 48 A P$
$\frac{C P}{A P} = \frac{4}{3}$

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p (m) = m^{3} + 2 m^{2} - m + 10

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- - \to P A + - - \to C P

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1.01 \times 10^{5}

= 1000 k g / m^{3}

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