If $p (m) = m^{3} + 2 m^{2} - m + 10$ then $p (a) + p (- a) =$ ?

Open in App

Solution

Given that,
$P (m) = m^{3} + 2 m^{2} - m + 10$

$P (a) + P (- a) = [a^{3} + 2 a^{2} - a + 10] + [(- a)^{3} + 2 (- a)^{2} - (- a) + 10]$

$= a^{3} + 2 a^{2} - a + 10 + [- a^{3} + 2 a^{2} + a + 10]$

$= a^{3} + 2 a^{2} - a + 10 - a^{3} + 2 a^{2} + a + 10$

$= 4 a^{2} + 20$

Suggest Corrections

Similar questions

-

-

-

-

$\frac{C P}{P A} = \frac{m}{3}$ .Find $m$

(2 m^{2} - 3 m + 10) \div (m - 5)

L = (20 + p m 0.01) m

B = (10 \pm 0.02) m

L / B

L = (20 \pm 0.01) m

B = (10 \pm 0.02) m

Join BYJU'S Learning Program