F x -1-sin x- - -2x 4-cos x- 8x3- 3 x-2 f - -2 if f x is continuous at x- -2 is -a- 2b- Find b-a

Put π/2 x=t nbsp; Ltt→ 01 cos t/ ( 2t )^4.sin t{ ( π 2t )^3 π ^3} nbsp;Applying factors of a^3 b^3 nbsp; =Ltt→ 02sin ^2 ( t/2 ).t/ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Continuity of a Function

f x =1-sin x/...

Question

$f (x) = \frac{1 - sin x}{{(π - 2 x)}^{4}} . cos x . (8 x^{3} - π^{3}) (x \neq \frac{π}{2})$ $f (π / 2)$ if $f (x)$ is continuous at $x = π / 2$ is $- \frac{a π^{2}}{b} .$ Find $b - a$

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = \frac{\sqrt{2} - \sqrt{1 + s i n x}}{c o s x}

x \neq π / 2

x = π / 2

f (π / 2)

x = π

f (x) = \frac{\sqrt{2 + c o s x - 1}}{(π - x^{2})}

x \neq π

f (π)

f (x) = \frac{1 - sin x}{sin 2 x}, x \neq \frac{π}{2}

f (x)

x = \frac{π}{2}

f (\frac{π}{2})

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{1 - {sin}^{3} x}{3 {cos}^{2} x}, i f x < \frac{π}{2} a, i f x = \frac{π}{2} \frac{b (1 - sin x)}{{(π - 2 x)}^{2}}, i f x > \frac{π}{2} \end{matrix}

f (x)

x = \frac{π}{2}

a

b

f (x) = \frac{1 - sin x}{(π - 2 x)^{2}}

x \neq \frac{π}{2}

x = \frac{π}{2}

f (\frac{π}{2}) .

Join BYJU'S Learning Program