The correct option is C NaOH solution
Fe3+ and Al3+ both beongs to group IIIrd of inorganic analysis and both are precipitated as their hydroxides on adding group reagent, ie, NH4OH in presence of NH4Cl.
Fe3++3OH−⟶Fe(OH)3
Al3+3OH−⟶Al(OH)3
but only ppt of Al(OH)3 is soluble in NaOH solution.