Question

$\frac{17}{15}\times \frac{17}{15}+\frac{2}{15}\times \frac{2}{15}-\frac{17}{15}\times \frac{4}{15}$ is equal to:

• A. $0$
• B. $1$
• C. $10$
• D. $11$

Answer 1

The correct option is B $1$

Given exp $=\frac{17}{15}\times \frac{17}{15}+\frac{2}{15}\times \frac{2}{15}-2\times \frac{17}{15}\times \frac{2}{15}$
$={\left(\frac{17}{15}\right)}^2+{\left(\frac{2}{15}\right)}^2-2\times \frac{17}{15}\times \frac{2}{15}$
$={(\frac{17}{15}-\frac{2}{15})}^2$ [Using $a^2+b^2-2ab=(a-b{)}^2$]
$={\left(\frac{15}{15}\right)}^2=1^2=1$