$\frac{5 a^{2} + 4 b + a^{2} b + 20}{b + 5}$ =..........

a^{2} + 5

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a^{2} + 4

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b + 5

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b^{2} + 4

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Solution

The correct option is B $a^{2} + 4$
$\frac{5 a^{2} + 4 b + a^{2} b + 20}{b + 5}$

$= \frac{5 a^{2} + a^{2} b + 4 b + 20}{b + 5}$

$= \frac{a^{2} (b + 5) + 4 (b + 5)}{(b + 5)}$

$= \frac{(a^{2} + 4) (b + 5)}{b + 5} = a^{2} + 4$

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5a2+4b+a2b+20b+5=..........

The correct option is B a2+45a2+4b+a2b+20b+5=5a2+a2b+4b+20b+5=a2(b+5)+4(b+5)(b+5)=(a2+4)(b+5)b+5=a2+4

$\frac{5 a^{2} + 4 b + a^{2} b + 20}{b + 5}$ =..........

The correct option is B $a^{2} + 4$
$\frac{5 a^{2} + 4 b + a^{2} b + 20}{b + 5}$

$= \frac{5 a^{2} + a^{2} b + 4 b + 20}{b + 5}$

$= \frac{a^{2} (b + 5) + 4 (b + 5)}{(b + 5)}$

$= \frac{(a^{2} + 4) (b + 5)}{b + 5} = a^{2} + 4$