$\frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)} =$

- \frac{63}{25} + \frac{16}{25} i .

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- \frac{63}{25} - \frac{16}{25} i .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{63}{25} + \frac{16}{25} i .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{63}{25} - \frac{16}{25} i .

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Solution

The correct option is D $\frac{63}{25} - \frac{16}{25} i .$
Given, $\frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)}$

$∴ \frac{(3 - 2 i) (2 + 3 i) (1 - 2 i) (2 + i)}{(1 + 4) (4 + 1)} = \frac{(12 + 5 i) (4 - 3 i)}{25}$

$= \frac{(48 + 15) + i (20 - 36)}{25}$
$= \frac{63}{25} - \frac{16}{25} i .$
Ans: D

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Question 63.
$\frac{16}{25} > \frac{13}{25}$

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i + 2 i^{2} + 3 i^{3} + \dots

The value of x in5x + 10 = 25 is:

25^{63} \times 63^{25}

25^{63} \times 63^{25}

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