Question

$\frac{\tan {45}^{\circ }}{\text{cosec}{30}^{\circ }}+\frac{\sec {60}^{\circ }}{\cot {45}^{\circ }}-\frac{5\sin {90}^{\circ }}{2\cos 0^{\circ }}$

Answer 1

$\frac{\tan {45}^0}{\csc {30}^0}+\frac{\sec {60}^0}{\cot {45}^0}-\frac{5\sin {90}^0}{2\cos 0^0}$

$=\frac{1}{2}+\frac{2}{1}-\frac{5\left(1\right)}{2\left(1\right)}$

$=\frac{5}{2}-\frac{5}{2}$
$=0$