H 2 S g - Cl 2 g - 2HCl g -S s The reaction is interpreted as-

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Oxides of Sulphur

H 2 S g + Cl ...

Question

$H_{2} S (g) + {C l}_{2} (g) \to 2 H C l (g) + S (s)$ The reaction is interpreted as:

H_{2} S

is getting oxidised and

{C l}_{2}

is getting reduced.

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H_{2} S

is getting reduced and

{C l}_{2}

is getting oxidised

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Only

H_{2} S

is oxidised

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Both

H_{2} S

and

{C l}_{2}

are reduced

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= k [C l_{2}] [H_{2} S]

i s / a r e

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