State which substance is getting oxidised and reduced in the following equation:
MnO₂+ 4HCl -> MnCl₂+ 2H₂O + Cl₂

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Solution

Substance oxidized : HCl

Substance reduced : MnO2

Oxidizing agent: : MnO2

Reducing agent : HCl

Here, Mn is in +4 oxidation state in MnO2while it is in +2 Oxidation state in MnCl2 , thus a decrease in oxidation no. shows that MnO2undergo reduction, and so it will work as an oxidizing agent.

Similarly, in HCl, Chlorine is in -1 oxidation state while it becomes 0 in Cl2 , the increase in oxidation no. shows that HCl undergoes oxidation and so it will act as a reducing agent.

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Similar questions

Q. Which substance/ion is oxidised and which substance/ion is reduced in the following reaction?

M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}

Q. The substance that is oxidised in the following chemical reaction is:

M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}

Identify the substance oxidized, substance reduced, oxidising agent and reducing agent.
$M n O_{2}$ + $4 H C l$ $\to$ $M n {C l}_{2}$ + $2 H_{2} O$ + ${C l}_{2}$ .

Q. (a) Define (i) oxidation, and (ii) reduction.
(b) Identify the substances oxidised and reduced in the chemical reaction:
MnO₂ + 4HCl → MnCl₂+ Cl₂+ 2H₂O

Q. In the following reaction, identify the species oxidised, the species reduced, the oxidising agent and the reducing agent.

4 H C l + M n O_{2} \to M n C l_{2} + 2 H_{2} O + C l_{2}

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State which substance is getting oxidised and reduced in the following equation: MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2

State which substance is getting oxidised and reduced in the following equation:
MnO₂+ 4HCl -> MnCl₂+ 2H₂O + Cl₂