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Question

π/20dx4cos2x+9sin2x=


A

π/6

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B

π/12

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C

π/36

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D

π/72

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Solution

The correct option is B

π/12


π/20dx4cos2x+9sin2x

=π/20sec2x dx4+9tan2x

Put 3tanx=t
π/20sec2x dx4+9tan2x=130dt4+t2=π12


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