CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

π/20dx4cos2x+9sin2x=


A

π/6

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

π/12

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

π/36

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

π/72

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

π/12


π/20dx4cos2x+9sin2x

=π/20sec2x dx4+9tan2x

Put 3tanx=t
π/20sec2x dx4+9tan2x=130dt4+t2=π12


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parametric Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon