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Question

2x(f(x)+f(x)log2)dx is equal to

A
2xf(x)+c
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B
2xlog2+c
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C
2xf(x)+c
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D
2x+c
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Solution

The correct option is C 2xf(x)+c
2x(f(x)+f(x)log2)dx
Let 2xf(x)=t2x(f(x)+f(x)log2)dx=dt
dt=t+c=2xf(x)+c

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