$\int \frac{8 x + 5}{4 x^{2} + 5 x + 6} d x$

Open in App

Solution

Let $t = 4 x^{2} + 5 x + 6 d t = 8 x + 5 d x ⟹ \int \frac{1}{t} d t = log t log (4 x^{2} + 5 x + 6) + c$

Suggest Corrections

Similar questions

\int \frac{2 x + 5}{x^{2} + 5 x + 6} d x

\int \frac{(6 x - 5)}{2 \sqrt{3 x^{2} - 5 x + 6}} d x =

\int \frac{2 x + 5}{x^{2} + 5 x + 6} d x

\int_{- 1}^{2} \sqrt{5 x + 6} d x

\int \frac{x^{2} + 1}{x^{2} - 5 x + 6} d x

Join BYJU'S Learning Program