$\int e^{2 x + 5} d x$ is equal to
(where $C$ is constant of integration)

\frac{e^{2 x + 5}}{5} + C

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\frac{e^{2 x + 5}}{2} + C

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\frac{e^{2 x + 5}}{10} + C

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\frac{e^{2 x + 5}}{3} + C

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Solution

The correct option is B $\frac{e^{2 x + 5}}{2} + C$
$\int e^{2 x + 5} d x = e^{2 x + 5} \times \frac{1}{2} + C$
$(∵ \int e^{a x + b} d x = e^{a x + b} \times \frac{1}{a} + C, a \neq 0)$

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