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Question

ex(1+n.xn1x2n)(1xn)1x2n dx is equal to

A
ex1xn1+xn+c
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B
ex1+xn1xn+c
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C
ex1xn1+xn+c
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D
ex1+xn1xn+c
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Solution

The correct option is B ex1+xn1xn+c
Let I=ex(1+nxn1x2n)(1xn)1x2ndx
=ex(1x2n(1xn)1x2n+nxn1(1xn)1x2n)
Let T=1x2n(1xn)1x2n=1xn1xn
dTdx=nxn1(1xn)1x2n
I=exT=ex1+xn1xn

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