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Question

1(14xx2)dx

A
sin1x+2(5)
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B
sin1x2(5)
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C
cos1x+2(5)
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D
sin1x+2(5)
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Solution

The correct option is D sin1x+2(5)
Let I=1(14xx2)dx=dx[5(x+2)2]
Using dxa2x2=sin1xa
We get
I=sin1x+25
Hence, option 'D' is correct.

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