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B
lnx−27ln(1−x7)+c
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C
lnx−27ln(1+x7)+c
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D
lnx+27ln(1−x7)+c
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Solution
The correct option is Clnx−27ln(1+x7)+c Given , ∫1−x7x(1+x7)dx ⇒∫1+x7−2x7x(1+x7)dx ⇒∫(1x−2x61+x7)dx ⇒∫(1x−27(7x61+x7))dx ⇒lnx−27ln(1+x7)+c Hence, option 'C' is correct.